RE: [sv-ec] Mantis 2055 : coverage bin distribution

From: Bresticker, Shalom <shalom.bresticker_at_.....>
Date: Thu Oct 18 2007 - 04:31:40 PDT
A revised proposal is attached and also in Mantis.
 
Shalom


________________________________

	From: owner-sv-ec@server.eda.org
[mailto:owner-sv-ec@server.eda.org] On Behalf Of Bresticker, Shalom
	Sent: Thursday, October 18, 2007 12:31 PM
	To: Swapnajit Chakraborti; sv-ec@server.eda.org
	Subject: RE: [sv-ec] Mantis 2055 : coverage bin distribution
	
	
	Good catch.
	 
	The difference was not intended, and should apply to the case of
a fixed number of bins as well. I will revise the proposal to apply
there as well.
	 
	Thanks,
	Shalom


________________________________

		From: owner-sv-ec@server.eda.org
[mailto:owner-sv-ec@server.eda.org] On Behalf Of Swapnajit Chakraborti
		Sent: Thursday, October 18, 2007 12:21 PM
		To: sv-ec@server.eda.org
		Cc: Swapnajit Chakraborti
		Subject: [sv-ec] Mantis 2055 : coverage bin distribution
		
		
		Mantis 2055 mentions a modified formula to be used for
coverage bin distribution specifically for section 18.5.2, which deals
with automatic bins. 
		 
		The distribution technique for sized vector bins (ref
the underlined line shown in the excerpt below) is different from the
distribution scheme described in Mantis 2055. 
		 
		Is this difference intended or both these distribution
schemes should match so that we have a consistent bin distribution
method?
		 
		Regds,
		Swapnajit.
		 
		 
		 
		 
		---------------------------excerpt from
P1800-2008-draft3aPROTECTED.pdf (section 18.5)
------------------------------------------
		 
		If a fixed number of bins is specified and that number
is smaller than the specified number of values, then
		the possible bin values are uniformly distributed among
the specified bins. The first 'n' specified values are
		assigned to the first bin, the next 'n' specified values
are assigned to the next bin, etc. Duplicate values are
		retained; thus the same value can be assigned to
multiple bins. If the number of values is not divisible by the
		number of bins, then the last bin will include the
remaining items. For example:
		 
		
		bins fixed [4] = {1:10, 1, 4, 7};
		 
		
		The 13 possible values are distributed as follows:
<1,2,3>, <4,5,6>, <7,8,9>, <10,1,4,7>. If the number of
		bins exceeds the number of values, then some of the bins
will be empty.
		

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Received on Thu Oct 18 04:32:24 2007

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