RE: [sv-bc] scope of break/continue within foreach loop

should have been

"foreach (a[x,y])"

Shalom

________________________________
From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org] On Behalf Of Daniel Mlynek
Sent: Wednesday, June 02, 2010 4:42 PM
To: 'Jonathan Bromley'
Cc: 'Paul Graham'; 'sv-bc'
Subject: RE: [sv-bc] scope of break/continue within foreach loop

The syntax proposed by you (foreach (a[x][y]) ) is not valid according to LRM. Froeach can take :

hierarchical_array_identifier

as an argument, not array member select.

DANiel

________________________________
From: Jonathan Bromley [mailto:jonathan.bromley@verilab.com]
Sent: Wednesday, June 02, 2010 12:44 PM
To: Daniel Mlynek
Cc: Paul Graham; sv-bc
Subject: Re: [sv-bc] scope of break/continue within foreach loop

I agree with Daniel. If break takes you right out of foreach, you can easily get
the "break out of inner loop" behaviour by splitting the loop:

   foreach (a[x,y]) begin
      ...mess with a[x][y];
      break; // should break out completely
   end

   foreach (a[x]) begin
     foreach (a[x][y]) begin // this scans only y, right????
       ...mess with a[x][y];
       break; // breaks out of y-loop only
     end
   end

But if break only breaks the innermost loop, it's troublesome to break
out of the whole "foreach".

--
Jonathan Bromley
On Wed, Jun 2, 2010 at 11:31 AM, Daniel Mlynek <daniel.mlynek@aldec.com.pl<mailto:daniel.mlynek@aldec.com.pl>> wrote:
Imho break should  break the whole loop any other hahviour would be just
hard to understand ie:
module top;
int arr[10][3];
initial
foreach (arr[i,j]) begin
       $display(i, j);
       if (i==2) break; //this breaks the foreach and finishes whole tests
end
endmodule
DANiel
-----Original Message-----
From: owner-sv-bc@eda.org<mailto:owner-sv-bc@eda.org> [mailto:owner-sv-bc@eda.org<mailto:owner-sv-bc@eda.org>] On Behalf Of Paul
Graham
Sent: Tuesday, June 01, 2010 11:55 PM
To: sv-bc
Subject: [sv-bc] scope of break/continue within foreach loop
A foreach statement with multiple variables is defined as equivalent to a
set of nested for loops.  If a break statement is executed in the body of a
forever loop, does it break out of the innermost of these nested for loops,
or does it break out of the outermost?  Likewise for a continue statement.
I guess it should be the outermost loop.  Could this be clarified?
Paul
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