In my opinion, since case
equality/inequality operators are
allowed on any operand, then wild equality/inequality should
operate in same
way. I am not sure about string operand though, as for the
following case all
tools fail.
module m;
string i, j;
wire o;
assign o = (i===j);
endmodule
I am not sure why.
Regards
Surya
-------- Original Message --------
Subject: Re: [sv-bc] Is wild equality/inequality operator
allowed on aggregate
expression?
From: Bresticker, Shalom <shalom.bresticker@intel.com>
To: Surya Pratik Saha <spsaha@cal.interrasystems.com>
Cc: "sv-bc@eda.org"
<sv-bc@eda.org>
Date: Monday, October 11, 2010 7:28:34 PM
Good
point.
The
statement
you quote was added in Mantis 1594.
The
table
entry I quoted was earlier, so Mantis 1594 should be
considered to take
precedence.
However,
what
about other non-intergral operands?
Shalom
Hi Shalom,
It is also written in the LRM:
The wildcard equality operator is equivalent to the
logical equality operator
if its operands are class objects, chandles or the
literal null.
Is it not conflicting and so confusing then?
Regards
Surya
-------- Original Message --------
Subject: Re: [sv-bc] Is wild equality/inequality operator
allowed on aggregate expression?
From: Bresticker, Shalom <shalom.bresticker@intel.com>
To: Surya Pratik Saha <spsaha@cal.interrasystems.com>,
sv-bc@eda.org
<sv-bc@eda.org>
Date: Monday, October 11, 2010 7:11:01 PM
Table 11-1 says that the operand data types for the binary wildcard equality operators are 'integral'.
Shalom
-----Original Message-----
From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org] On Behalf Of
Surya Pratik Saha
Sent: Monday, October 11, 2010 3:34 PM
To: sv-bc@eda.org
Subject: [sv-bc] Is wild equality/inequality operator allowed on
aggregate expression?
Hi,
Is wild equality/inequality operator allowed on aggregate expression? I
am getting different results from different standard tools for the
following case?
typedef struct { logic l; } T;
module m;
T i, j;
wire o;
assign o = (i==?j);
endmodule
I did not get any explicit answer from LRM.
--
Regards
Surya
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