Re: [sv-bc] Email Vote: Respond by 8AM PDT Wed Apr 20

And does it really make sense for a scalar to have a signedness? How
can a bit be signed or unsigned?

-- Brad

On Wed, Apr 13, 2011 at 11:07 AM, Brad Pierce <brad_pierce@acm.org> wrote:
> "The data types time, bit, reg, and logic default to unsigned, as do
> arrays of these types."
>
> The "as do arrays of these types" sort of makes sense for scalar
> types, but it seems redundant and really means "packed arrays". Any
> reason we shouldn't strike that phrase?
>
> -- Brad
>
> 2011/4/13 Bresticker, Shalom <shalom.bresticker@intel.com>:
>> Brad,
>>
>> The preceding sentence says, "The data types byte, shortint, int, integer, and longint default to signed."
>>
>> That is, the paragraph describes the signedness of each of the integral data types.
>>
>> "time" is the only one missing.
>>
>>
>> Shalom
>>
>>
>>> -----Original Message-----
>>> From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org] On Behalf Of
>>> Brad Pierce
>>> Sent: Wednesday, April 13, 2011 6:23 PM
>>> To: Maidment, Matthew R
>>> Cc: SV-BC
>>> Subject: Re: [sv-bc] Email Vote: Respond by 8AM PDT Wed Apr 20
>>>
>>> I vote yes on all, except the last one
>>>
>>> > SVDB  3384 ___Yes   _X__No
>>> > http://www.eda.org/svdb/view.php?id=3384
>>>
>>> The time type doesn't fit naturally into a sentence about scalar
>>> types. An array of times defaults to unsigned? Doesn't every packed
>>> array of anything default to unsigned, and unpacked arrays don't have
>>> signedness?
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