The current [0:N-1] ordering was chosen to match array index ordering in C/C++. IMHO, [N] should never been allowed as a shortcut in a language that already supported ranges in either order because of the confusion it creates. Erik's workaround example is proof of that. But it's too late to change the default range order now for an unpacked array now. Dave From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org] On Behalf Of Brad Pierce Sent: Tuesday, September 30, 2014 1:44 PM To: sv-bc@eda.org Subject: [sv-bc] RE: Q: [N] array bounds legal for unpacked but not packed arrays? [In reply to http://www.eda.org/sv-bc/hm/11620.html .] The current [0:N-1] default for unpacked array dimensions is also significant (and annoying). With the hardware order [N-1:0] you can split/merge dimensions fluidly, as in typedef struct {int x, y;} T; module test#(N=2,M=3) ( output T A_2D[(2**N)-1:0][(2**M)-1:0] , output T A_1D[(2**(N+M))-1:0] ); logic [N-1:0] idx_N; logic [M-1:0] idx_M; always_comb begin for (int i = 0; i < 2**N; i++) begin for (int j = 0; j < 2**M; j++) begin idx_N = i; idx_M = j; A_2D[idx_N][idx_M] = '{i,j}; A_1D[{idx_N,idx_M}] = '{i,j}; assert final (A_2D[idx_N][idx_M] == A_1D[{idx_N,idx_M}]); end end end endmodule But with the [0:N-1] default you need to flip the order of dimensions in the indexes, as in typedef struct {int x, y;} T; module test#(N=2,M=3) ( output T A_2D[0:(2**N)-1][0:(2**M)-1] , output T A_1D[0:(2**(N+M))-1] ); logic [N-1:0] idx_N; logic [M-1:0] idx_M; always_comb begin for (int i = 0; i < 2**N; i++) begin for (int j = 0; j < 2**M; j++) begin idx_N = i; idx_M = j; A_2D[idx_N][idx_M] = '{i,j}; A_1D[{idx_M,idx_N}] = '{i,j}; assert final (A_2D[idx_N][idx_M] == A_1D[{idx_M,idx_N}]); end end end endmodule -- Brad -- This message has been scanned for viruses and dangerous content by MailScanner<http://www.mailscanner.info/>, and is believed to be clean. -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.Received on Tue Sep 30 13:58:30 2014
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