Shalom, During discussion of the array methods in the SV-EC meeting today, we realized that there is actually a way to force a sum to be done in a wider width than the array elements, by using the "with" clause. When you use a "with" clause, the thing that is summed is the expression specified in that clause. Presumably the width of the reduction method result is the width of the expression in the "with" clause. The default when the clause is not provided is for the expression to be the array item itself. If that is not wide enough, you can provide a "with" clause that has the same value as the item itself, but using one of the usual tricks for forcing that value to be wider. For example: logic bit_arr [1024]; total = bit_arr.sum with (item + 0); By adding the 32-bit constant 0, the items will be extended to 32 bits before being summed. It may not be obvious or pretty, but it turns out it can be done. Steven Sharp sharp@cadence.comReceived on Mon Jul 31 13:54:15 2006
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