RE: [sv-bc] subroutine argument default question

Shalom,

 

It needs to be that way because of static (fixed) type and name binding.
The compiler needs a fixed target when it compiles the subroutine
declaration, especially if the default is an expression of identifiers.

 

Dave

 

________________________________

From: owner-sv-bc@server.eda.org [mailto:owner-sv-bc@server.eda.org] On
Behalf Of Bresticker, Shalom
Sent: Tuesday, July 31, 2007 6:35 AM
To: sv-bc
Subject: [sv-bc] subroutine argument default question

 

Hi, 

Subroutine defaults are evaluated in the scope containing the subroutine
declaration, not the subroutine call. I think property and sequence
defaults work the same way.

How important is that? 
Why could not the default be evaluated as though the call were written
with the default expression explicitly appearing in the subroutine call?

How important is the back-compatibility issue? 

If for example, the default expression were a[i], the variable pointed
to would change from call to call anyway, depending on the value of I,
and defaults do not have to be constant expressions.

Thanks, 
Shalom 

 

Shalom Bresticker 
Intel Jerusalem LAD DA 
+972 2 589-6852 
+972 54 721-1033 


-- 
This message has been scanned for viruses and 
dangerous content by MailScanner <http://www.mailscanner.info/> , and is

believed to be clean. 

-- 
This message has been scanned for viruses and
dangerous content by MailScanner, and is
believed to be clean.