Question on timeprecision

Subject: Question on timeprecision
From: David Smith (david_smith@avanticorp.com)
Date: Thu Jul 26 2001 - 14:12:39 PDT

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Greetings,

I am reviewing the discussion we had in the last meeting and rereading the Superlog_ESS document.

I have a question on "timeprecision" that I would like either confirmation or clarification on.

On page 11 it states that "The time step is set globally to the smallest precision, as in Verilog, or to 1fs if no timeprecision isused.".
This states the result on the time step if no timeprecision is specified (and one assumes that there is no value set using `timescale).

My question is what happens to the rounding? It would appear that, since the time step controls the resolution of events it would also effect
the rounding of the value. This is not explicit (perhaps obvious).

Thanks
David

David W. Smith
Architect

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