RE: [sv-bc] Typo in description of inside operator

I believe "left-hand" is correct.

11.4.6 says, "The wildcard equality operator (==?) and inequality operator (!=?) treat X and Z values in a given bit position
of their right operand as a wildcard. X and Z values in the left operand are not treated as wildcards."

and

11.4.13 says about the inside operator, "Integral expressions use the wildcard equality (==?) operator".

Regards,
Shalom

> -----Original Message-----
> From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org] On Behalf Of
> Paul Graham
> Sent: Monday, August 02, 2010 10:53 PM
> To: sv-bc
> Subject: [sv-bc] Typo in description of inside operator
>
> Sorry if this is a known issue. The text describing the inside
> operator says:
>
> As with wildcard equality, an x or z in the expression on the left-
> hand
> side of the inside operator is not treated as a do-not-care.
>
> It should be "right-hand", not "left-hand".
>
> Paul

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