Brad, Thanks for your reply. Does that mean, the size (not the type) of an assignment expression is always context independent ?? In other words, Is it always self-determined ?? The page you pointed out only talks about the types and it mentions size only as a passing reference for concatenations. I wish there was a line explicitly saying something like: The size of an assignment expression is always self-determined. - Krishna. Brad Pierce wrote: > The semantics of assignment expressions are described > at the top of p.71 in the balloting draft. Here's > how I interpret them -- > > a = b * (c+=3); > > is > > a = b * (c=c+3); > > is > > a = b * f(c,c+3); > > where, for T==$typeof(c), > > function automatic T f(output T LHS, input T RHS); > LHS = RHS; > return LHS; > endfunction > > The assignment to c is a context independent of the > assignment to a. > > -- Brad > > -----Original Message----- > From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org]On Behalf Of > Krishna Garlapati > Sent: Friday, March 25, 2005 3:31 PM > To: sv-bc@eda.org > Subject: [sv-bc] Pls Clarify: Expression Sizing and assignment > operators. > > > > I hope I am not raising something that has been discussed already. > > Section 7.7, D4 says that SystemVerilog follows the same sizing > rules as Verilog. > > Consider: > > a = b * (c+=3); > > My question is: Does the size of the 2nd operand in the += assign > expression (32 bits) effect the size of the full expression ?? > (I hope not) > > I wish the LRM would specifically say a yes or no and explain it > since this is unique to SystemVerilog. > > -- Krishna 408-215-6152Received on Fri Mar 25 16:47:23 2005
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